To solve the problem we must know about the area.
Part 1
Area of a Triangle
The area of a triangle is half the product of the base of the triangle and the height of the triangle.
[tex]\rm{ Area \triangle = \dfrac{1}{2} \times base \times height\\
[/tex]
From all the given statements, statement 1 is the best way to explain, the sum of the areas of the two white squares in figure 2 is the same as the area of the white square in figure 1.
Part 2 - Explanation
Solution
As given the Area of both the big squares of figure 1 and figure 2 are equal because the side of both the squares is equal, therefore, (a+b).
figure 1,
Big square = (a+b)²,
figure 2,
Big square = (a+b)²,
Also, the sides of the 4 triangles are also the same giving the same area for all the 8 triangles from Figures 1 and 2.
figure 1,
area for 1 triangle = [tex]\bold{\dfrac{ab}{2}}[/tex]
area for 4 triangle = [tex]\bold{4\times \dfrac{ab}{2}}[/tex]
area for white square = big square area - 4 triangles area
=(a+b)² - ([tex]\bold{4\times \dfrac{ab}{2}}[/tex])
figure 2,
area for 1 triangle = [tex]\bold{\dfrac{ab}{2}}[/tex]
area for 4 triangle = [tex]\bold{4\times \dfrac{ab}{2}}[/tex]
area for white square = big square area - 4 triangles area
=(a+b)² - ([tex]\bold{4\times \dfrac{ab}{2}}[/tex])
Hence, the given statements, statement 1 is the best way to explain, the sum of the areas of the two white squares in figure 2 is the same as the area of the white square in figure 1.
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