Respuesta :

carlosego

Answer: last option

Step-by-step explanation:

The parent function of a quadratic function is :

[tex]y=x^2[/tex]

The graph shown is the graph of parent function shifted 3 units down:

[tex]y=x^2-3[/tex]

Then the second option is not correct.

Now you must choose any point of the shaded region and substitute it into the inequality 1 and 3:

[tex]x=2[/tex]

[tex]y=0[/tex]

[tex]0\geq(2)^2-3\\0\geq1[/tex] ( THIS IS NOT TRUE).

[tex]0\leq(2)^2-3\\0\leq1[/tex] (TRUE)

zainebamir540

Answer:

Choice 3 is the inequality for this graph.

Step-by-step explanation:

We have given the graph.

We have to find the inequality for this graph.

The parent function is :

f(x) = x²

When we shift the parent function 3  units down we get,

f(x) = x² - 3

From this, it is clear that the choice B is not correct.

Now check the other inequalities we get,

Take any point from the shaded region and put in the 1 and 3 choice we get,

x= -2 and y = 0 put it in the inequality one by one we get,

1ST CHOICE:

y >= x²-3

0 >= (-2)²-3

0 >= 4-3

0>= 1

It is not true.

3rd choice:

y<= x² - 3

0<= (-2)² -3

0<=1

This is true.

So, choice 3 is correct.

0 >=-1