Respuesta :

Answer: THE GRAPH IS ATTACHED.

Step-by-step explanation:

Find the vertex of the parabola (It is a parabola because the equation is quadratic), as following:

[tex]x=\frac{-b}{2a}[/tex]

Where:

a=1

b=-2

Then:

[tex]x=\frac{-(-2)}{2*1}=1[/tex]

Substitute this into the equation to obtain y:

[tex]y=1^{2}-2(1)+3=2[/tex]

The point of the vertex is (1,2)  

The sign of a is positive, therefore, the parabola has a minimum.

 Substitute x=0 into the equation to find y-intercept:

[tex]y=0^2-2(0)+3\\y=3[/tex]

You know that this point is (0,3)

Know that the parabola has a minimum, the vertex and the y-intercept, you can graph it as you can see in the image attached.

Ver imagen carlosego

Quadratic equation

According to the question, we are to graph the quadratic equation [tex] f(x) = x^2 - 2x + 3[/tex]

First, we need to find the vertex of the parabola as shown:

[tex]x=\frac{-b}{2a}\\ x = \frac{2}{2}\\ x = 1[/tex]

Substitute x = 1 intp the quadratic function

[tex]y = 1^2 - 2(1) + 3\\ y = 1-2+3\\ y = 2[/tex]

Hence the vertex of the parabola will be (1,2)

Next is to get the y-intercept, the point where x = 0

[tex]y = 0^2 -2(0)+ 3\\ y = 3[/tex]

The y-intercept is at (0, 3)

Find the graph of the function attached.

Learn more on the quadratic graph here: https://brainly.com/question/10606041

Ver imagen abidemiokin