Respuesta :
Answer: THE GRAPH IS ATTACHED.
Step-by-step explanation:
Find the vertex of the parabola (It is a parabola because the equation is quadratic), as following:
[tex]x=\frac{-b}{2a}[/tex]
Where:
a=1
b=-2
Then:
[tex]x=\frac{-(-2)}{2*1}=1[/tex]
Substitute this into the equation to obtain y:
[tex]y=1^{2}-2(1)+3=2[/tex]
The point of the vertex is (1,2)
The sign of a is positive, therefore, the parabola has a minimum.
Substitute x=0 into the equation to find y-intercept:
[tex]y=0^2-2(0)+3\\y=3[/tex]
You know that this point is (0,3)
Know that the parabola has a minimum, the vertex and the y-intercept, you can graph it as you can see in the image attached.
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Quadratic equation
According to the question, we are to graph the quadratic equation [tex] f(x) = x^2 - 2x + 3[/tex]
First, we need to find the vertex of the parabola as shown:
[tex]x=\frac{-b}{2a}\\ x = \frac{2}{2}\\ x = 1[/tex]
Substitute x = 1 intp the quadratic function
[tex]y = 1^2 - 2(1) + 3\\ y = 1-2+3\\ y = 2[/tex]
Hence the vertex of the parabola will be (1,2)
Next is to get the y-intercept, the point where x = 0
[tex]y = 0^2 -2(0)+ 3\\ y = 3[/tex]
The y-intercept is at (0, 3)
Find the graph of the function attached.
Learn more on the quadratic graph here: https://brainly.com/question/10606041
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