A solid conducting sphere with radius R = 0.390 m carries a net charge of +0.650 nC.
Electric field: Find the electric field: at a point 0.100 m outside the surface of the sphere.

The electric field generated by a charged sphere at a point outside the sphere is equivalent to the electric field generated by a single point charge, and it is given by

[tex]E=k\frac{Q}{r^2}[/tex]

where

[tex]k=9\cdot 10^9 Nm^2C^{-2}[/tex] is the Coulomb's constant

Q is the net charge

r is the distance from the centre of the sphere

In this problem, we have

[tex]Q=+0.650 nC=0.65\cdot 10^{-9}C[/tex]

[tex]r=0.390 m[/tex]

Substituting into the equation, we find

[tex]E=(9\cdot 10^9)\frac{(0.65\cdot 10^{-9}C)}{(0.390m)^2}=38.5 N/C[/tex]

A solid conducting sphere with radius R = 0.390 m carries a net charge of +0.650 nC. Electric field: Find the electric field: at a point 0.100 m outside the surface of the sphere.

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A solid conducting sphere with radius R = 0.390 m carries a net charge of +0.650 nC.
Electric field: Find the electric field: at a point 0.100 m outside the surface of the sphere.