Solve the answer for these problems
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[tex]S\frac{O}{H} C\frac{A}{H} T\frac{O}{A}[/tex]
Cos\frac{Adjacent}{Hypotenuse} \
[tex]Sine\frac{Oppositie}{Hypotenuse} Cos\frac{Adjacent}{Hypotenuse} Tan\frac{Oppositie}{Adjacent}[/tex]
1) You have the adjacent. Use these equations to find x and y:
[tex]C\frac{A}{H} T\frac{O}{A}[/tex]
[tex]x = cos11\frac{17.5}{x} \\x = \frac{17.5}{cos11}\\x = 17.82754216\\y = tan11\frac{y}{17.5} \\y = 17.5 * tan 11\\y = 3.40165541[/tex]
2) You have the hypotenuse. Use these equations to find x and y:
[tex]S\frac{O}{H} C\frac{A}{H}[/tex]
[tex]x = Sin27\frac{x}{15} \\x = Sin27* 15 \\x = 6.809587496\\y = Cos27\frac{y}{15}\\y = Cos27* 15 \\y = 13.36509786[/tex]
3) You have the adjacent. Use these equations to find x and y:
[tex]C\frac{A}{H} T\frac{O}{A}[/tex]
[tex]x = tan31.5\frac{x}{5} \\x = 5 * tan 31.5\\x = 3.064003941\\y = cos31.5\frac{5}{y} \\y = \frac{5}{cos31.5}\\y = 5.864138483\\\\[/tex]
4) You have the adjacent. Use these equations to find x and y:
[tex]C\frac{A}{H} T\frac{O}{A}[/tex]
[tex]x = sin52\frac{9}{x} \\x = \frac{9}{sin52}\\x = 11.42116394\\y = tan52\frac{9}{y} \\y = 9 / tan 52\\y = 7.031570639[/tex]