(7-5)2÷2)×(3+4+10)
[tex](7 - 5)2 \div 2) \times (3 + 4 + 10)[/tex]
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Assignment: [tex]\bold{Solve \ Equation: \ \left(\left(7-5\right)\cdot \:2\div \:2\right)\left(3+4+10\right)}[/tex]
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Answer: [tex]\boxed{\bold{34}}[/tex]
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Explanation: [tex]\downarrow\downarrow\downarrow[/tex]
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[ Step One ] Follow Order Of PEMDAS, Calculate Within Parenthesis
Note: [tex]\bold{PEMDAS: \ Parenthesis, \ Exponents, \ Multiply, \ Divide, \ Add, \ Subtract}[/tex]
[tex]\bold{\left(7-5\right)\cdot \:2\div \:2: \ 2}[/tex]
[ Step Two ] Rewrite Equation
[tex]\bold{2\left(3+4+10\right)}[/tex]
[ Step Three ] Calculate Within Parenthesis
[tex]\bold{3+4+10: \ 17}[/tex]
[ Step Four ] Rewrite Equation
[tex]\bold{2 \ \cdot \:17}[/tex]
[ Step Five ] Solve
[tex]\bold{= \ 34}[/tex]
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[tex]\bold{\rightarrow Mordancy \leftarrow}[/tex]