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A rectangle has a perimeter of (26x+16)cm and an area of (42x^2+51x+15)cm^2. Find the dimensions of the rectangle in terms of x.

Respuesta :

Answer:

The dimensions are:

[tex]3(2x+1)[/tex] by [tex](7x+5)[/tex]

Step-by-step explanation:

The area of the rectangle is given as

[tex]A=42x^2+51x+15[/tex]

The factored form of this quadratic trinomial gives the dimensions of the rectangle.

We factor 3 first to obtain;

[tex]A=3(14x^2+17x+5)[/tex]

We split the middle term to get;

[tex]A=3(14x^2+10x+7x+5)[/tex]

We factor within the parenthesis to get;

[tex]A=3(2x(7x+5)+1(7x+5))[/tex]

We factor further to get;

[tex]A=3(2x+1)(7x+5)[/tex]

The dimensions are:

[tex]3(2x+1)[/tex] by [tex](7x+5)[/tex]

Then the perimeter will be

[tex]2(6x+3+7x+5)=26x+16\:\:\:\boxed{\sqrt{} }[/tex]