A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=92t-16t^2. What is the maximum height that the ball will reach? Do not round your answer

Respuesta :

Answer:

132.25 feet

Step-by-step explanation:

Since the function is a quadratic representing height, and the coefficient of the t² is negative, the vertex of the parabola will be the maximum height achieved by the ball.  

The general form for a quadratic equation is ax² + bx + c,

here a is -16, and b is 92

To find the x coordinate of the vertex, use   x = -b/(2a)

We have x = -92/[2(-16)]

             

                     x = -92/-32

                         x= 23/8

Now plug that into the equation to find the y value, which will be the height...

y = 92(23/8) - 16(23/8)²

    y = 2116/8 - 16(529/64)

        y = 1058/4 - 529/4

              y = 529/4

                     y = 132.25

The maximum height that the ball will reach : 132.25 ft

Further explanation

Quadratic function is a function that has the term x²

The quadratic function forms a parabolic curve

The general formula is

f (x) = ax² + bx + c

where a, b, and c are real numbers and a ≠ 0.

The parabolic curve can be opened up or down determined from the value of a. If a is positive, the parabolic curve opens up and has a minimum value.   If a is negative, the parabolic curve opens down and has a maximum value

So the maximum is if a <0 and the minimum if a> 0.

The formula for finding the coordinates of the maximum and minimum points of the quadratic function is the same.

The maximum / minimum point of the quadratic function is

[tex]\rm -\dfrac{b}{2a},-\dfrac{D}{4a}[/tex]

Where

D = b²-4ac

h height of the ball is given by the function h (t) = 92t-16t².

so the value of a <0, then it has a maximum value

Because we are looking for maximum height, then we find the value of the y coordinate, with the formula

[tex]\rm -\dfrac{D}{4a}[/tex]

h (t) = 92t-16t²

a = -16 b = 92 c = 0

D = b²-4ac

D = 92²-4.-16.0

D = 8464

Value of y = maximum height (h):

[tex]\rm h=-\dfrac{D}{4a}\\\\h=-\dfrac{8464}{4\times -16}\\\\h=\boxed{132.25\:ft}}[/tex]

Learn more

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