Short answer: 1.99 m
Explanation:
PE=m*g*h ---> if we divide each side by m*g then we get [tex]\frac{PE}{m*h} =\frac{m*g*h}{m*g}[/tex] as we simplify the right side with m*g we get the final height formula as [tex]h=\frac{PE}{m*g}[/tex].
Thus, [tex]h=\frac{39}{2.0*9.8}[/tex] which results in h=1.9898 - if you need more than two decimals. Rounded up is approximately 2 meters.
The complete answer to your question is:
A 2.0-kilogram ball held above the floor has 39 joules of potential energy. The ball's height is about 2 meters above the floor.
