Respuesta :
ANSWER
[tex]7560[/tex]
EXPLANATION
The sum of interior angles of an n-gon is given by:
[tex] (n - 2)180[/tex]
When n=44, We get,
[tex](44 - 2) \times 180 [/tex]
[tex] = 42 \times 180[/tex]
[tex] = 7560[/tex]
[tex]7560[/tex]
EXPLANATION
The sum of interior angles of an n-gon is given by:
[tex] (n - 2)180[/tex]
When n=44, We get,
[tex](44 - 2) \times 180 [/tex]
[tex] = 42 \times 180[/tex]
[tex] = 7560[/tex]
Answer:
The sum of the interior angles of a 44-gon is 7560.
Step-by-step explanation:
We have to find the sum of the interior angles of a 44-gon.
As we know that the sum of interior angles of a n-gon (polygon with n-sides) is:
(n-2)×180
In this question, n = 44 so the above equation will be:
(44-2)×180
42× 180
The sum of the interior angles of a 44-gon is 7560.