Answer: 0.664 moles and 65.1 grams EDMENTUM USERS
Explanation: From the equation, we know that 1 mole of calcium phosphate produces 2 moles of phosphoric acid (H3PO4). So, if we know how many moles of calcium phosphate are present in 103 grams of Ca3(PO4)2, we can find the corresponding number of moles of H3PO4 that are produced during the reaction.
103 grams of calcium phosphate can produce 0.66 moles and 64.68 grams of phosphoric acid.
Mole is a measurement unit in Chemistry for large number of molecules , 1 mole is equal to 6.022 * 10²³ atoms.
A balanced Chemical Equation is given
6HCl + Ca₃(PO₄)₂ -> 3CaCl₂ + 2H₃PO₄.
Mass of phosphoric acid can be produced from 103 grams of calcium phosphate = ?
Moles of calcium phosphate = Mass / Molar mass = 103/310 = 0.33 moles
From the balanced equation we can see
The mole ratio for HCl : Ca₃(PO₄)₂ :CaCl₂ :H₃PO₄= 6 : 1 : 3 : 2
For 1 mole of Ca₃(PO₄)₂ , 2 moles of H₃PO₄ is produced
Therefore for 0.33 moles 0.66 moles of H₃PO₄will be produced
1 mole of H₃PO₄ = 98 grams of H₃PO₄
0.66 moles of H₃PO₄ = 0.66 * 98 = 64.68 grams of H₃PO₄ produced
Therefore 103 grams of calcium phosphate can produce 0.66 moles and 64.68 grams of phosphoric acid.
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