Answer:
See explanantion
Step-by-step explanation:
Consider the equation [tex]x^2-4x + 4 = 2x-1-x^2.[/tex] This equation consists of two parts:
- left part is defined by the function [tex]y=x^2-4x+4;[/tex]
- right part is defined by the function [tex]y=2x-1-x^2.[/tex]
Both these functions are quadratic and determine parabolas. The graph of the function
[tex]y=x^2-4x+4=(x-2)^2[/tex]
is parabola tangent to x-axis at point (2,0) with branches going up. The graph of the function
[tex]y=2x-1-x^2=-(x-1)^2[/tex]
is parabola tangent to x-axis at point (1,0) with branches going down (see diagram). As you can see from the diagram these two parabolas do not intersect, then there are no solutions.
