Answer:
[tex]4.2\cdot 10^{-32} m[/tex]
Explanation:
The De Broglie's wavelength of an object is given by:
[tex]\lambda=\frac{h}{mv}[/tex]
where
h is the Planck constant
m is the mass of the object
v is the speed of the object
In this problem, we have:
[tex]m=0.35 g=3.5\cdot 10^{-4} kg[/tex] is the mass of the pellet
[tex]v=162 km/h=45 m/s[/tex] is the speed of the pellet
Substituting into the equation, we find the wavelength of the pellet:
[tex]\lambda=\frac{6.63\cdot 10^{-34} Js}{(3.5\cdot 10^{-4}kg)(45 m/s)}=4.2\cdot 10^{-32} m[/tex]
