Answer with explanation:
Coordinates of point C = (6,0)
Coordinates of origin, O =(0,0)
So,we have to find a segment ,perpendicular to segment O C.
Let, Coordinate of Point P,which is obtained by rotation of point C,through 90 =(x,y)
→Slope of segment O C × Slope of Segment OP,which is obtained by rotation of segment ,O C after 90°= -1
[tex]\frac{0-0}{6-0} \times {\text{Slope of OP}}= -1\\\\ \frac{y-0}{x-0}=\frac{-6}{0}\\\\ -6 x=0\\\\x=0[/tex]
Also, OC=OP
→ O C²=O P²
∴→, x² + y²=6²
→ 0² +y²=6²
→ y²=6²
→y=6 ∧ y= -6
But we have to find point , C after a 90 degree in clockwise direction,which is = (0,-6)
Option A : (0,-6)
