Answer:
The surface area of the pyramid is [tex]55\ m^{2}[/tex]
Step-by-step explanation:
we know that
The surface area of the pyramid is equal to the area of the triangular base plus the area of the three lateral triangular faces
In this problem assume that the triangular base is an equilateral triangle
so
[tex]SA=\frac{1}{2}(4)(3.5)+3[\frac{1}{2}(4)(8)][/tex]
[tex]SA=7+48=55\ m^{2}[/tex]
