A 60.0 N circus performer performs a high wire act 5.0 m above ground. About how much gravitational potential energy does the performer have?

Respuesta :

Answer:

300 J

Explanation:

The gravitational potential energy of the performer is given by:

[tex]U=mgh[/tex]

where

(mg) is the weight of the performer, equal to the product between mass (m) and gravitational acceleration (g)

h is the height of the performer above the ground

In this problem, we have

(mg) = 60.0 N

h = 5.0 m

Substituting into the formula, we find

[tex]U=(60.0 N)(5.0 m)=300 J[/tex]

miya76
300 and if you need help use that formula
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