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An airplane is flying at an altitude of 2,910 m, has mass of 5,320 kg, and experiences a drag force of 530 N. How much force must the engines exert in order for the airplane to accelerate at 4.10 m/s2?

21,300 N

22,300 N

22,000 N

12,500 N

An airplane is flying at an altitude of 2910 m has mass of 5320 kg and experiences a drag force of 530 N How much force must the engines exert in order for the class=

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Answer

option A)

21,300 N

Explanation

Given that,

mass of plan = 5320kg

altitude at which plan is flying = 2910m

drag force = 530N

Number of forces acting on airplane

1)

Downward Force

weight = mg

           = 5320(9.81)

           = 52189.2 N

2)

Lifting Force

3)

Force that push the airplane forward, thrust

4)

Force that opposes thrust, drag

Since plane is horizontal it means weight = lifting force, this balance out.

So, in order to calculate thrust which engines exert in order for the airplane to accelerate at 4.10 m/s²

Fnet=ma or ΣF = ma,

where Fnet (or ∑F) is the net external force,

Fnet = Thrust - frictionalForce(drag)

ma = T - f

5320(4.10) = T - 530

21812 = T - 530

21812 - 530 = T

T = 21282 N

T ≈ 21,300 N

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