Answer:
Option A. [tex]432\ units^{2}[/tex]
Step-by-step explanation:
we know that
The area of the irregular figure is equal to the area of two trapezoids
The area of trapezoid is equal to
[tex]A=\frac{1}{2}(b1+b2)h[/tex]
where
b1,b2 are the parallel bases
h is the perpendicular distance between the parallel bases
Find the left trapezoid area
[tex]A1=\frac{1}{2}(4+25)(16)=232\ units^{2}[/tex]
Find the trapezoid area on the right
[tex]A2=\frac{1}{2}(25+15)(10)=200\ units^{2}[/tex]
The area of the irregular figure is
[tex]A=A1+A2=232\ units^{2}+200\ units^{2}=432\ units^{2}[/tex]
