Respuesta :

Answer:

The magnetic field would remain the same

Explanation:

The magnetic field inside a solenoid is given by

[tex]B=\mu_0 I n[/tex]

where

[tex]\mu_0[/tex] is the vacuum permeability

I is the current in the solenoid

n is the number of turns of the solenoid per unit length

In this problem, we have that the radius of the solenoid is doubled, while all other quantities remain the same. However, we see that the magnetic field inside the solenoid does not depend on its radius: therefore, the magnetic field does not change.

A long solenoid carries a current. If the radius of the solenoid were doubled, then the magnetic field would remain the same.

What will be the magnetic field inside the solenoid would If the radius of the solenoid were doubled?

The formula for the magnetic field inside the solenoid is given by

[tex]B=\mu_0In[/tex]

Here

[tex]\mu_0[/tex] = The vacuum permeability

I= is the current in the solenoid

n= is the number of turns of the solenoid per unit length

As it is given in the problem that if the radius of the solenoid were doubled while the other quantities remain the same.

Since the magnetic field of the solenoid does not depend upon the radius of the solenoid

so by changing the radius there will not be any change in the magnetic field of the solenoid

Thus the long solenoid carries a current. If the radius of the solenoid were doubled, then the magnetic field would remain the same.

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