Truck 2 has more kinetic energy than Truck 1
The Kinetic energy of mass m moving with velocity v is given by = [tex]1/2\times m\times v^{2}[/tex]
Let the mass of Truck 1 is [tex]m_{1}[/tex] = 200 Kg
Let the mass of Truck 2 is [tex]m_2[/tex] = 500 kg
Let Kinectic energy of Truck 1 is [tex]KE_1[/tex]
Let Kinectic energy of Truck 2 is [tex]KE_2[/tex]
[tex]KE_1[/tex]/[tex]KE_2[/tex] =[tex]1/2\times m_1\times v_1^{2}[/tex]/[tex]1/2\times m_2\times v_2^{2}[/tex]
Given that the velocity of both the trucks is equal hence
[tex]v_1=v_2[/tex] , hence both velocities will cancel out.
since
[tex]m_2[/tex] >[tex]m_{1}[/tex] as 500 kg > 200 kg
also in this case Kinetic Energy is directly proportional to the mass
so
[tex]KE_2[/tex] > [tex]KE_1[/tex]
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