Answer:
C. 2
Step-by-step explanation:
We have a circle described on the triangle. If one side of the triangle is the diameter of the circle, then the triangle is the right triangle.
Therefore m∠B = 90°.
AB is perpendicular to BC.
Let
k: y = m₁x + b₁ and l: y = m₂x + b₂
l ⊥ k ⇔ m₁m₂ = -1 ⇒ m₂ = - 1/m₁
We have the slope of BC m₁ = - 1/2.
Therefore the slope of AB m₂ = - 1/(- 1/2) = 2
