Answer:
Center: (0,0)
Radius: 3
The graph is attached.
Step-by-step explanation:
The equation of the circle has the form:
[tex](x -h)^{2}+(y-k)^{2}=r^{2}[/tex]
Where (h,k) is the point of the center of the circle and r is the radius of the circle.
If the center is at (0,0) and the radius is 3, you obtain the equation given in the problem:
[tex](x -0)^{2}+(y-0)^{2}=3^{2}[/tex]
[tex]x^{2}+y^{2}=9[/tex]
Therefore, the center is (0,0) and radius is 3.
You can graph the circle with its center at the origin and a radius of 3 as you can see in the figure attached.
