For this case we have a function of the form:
[tex]P = 100e^ {0.70t}[/tex]
Where,
- P: the number of colonies
- t: time in hours
By the time there are 300 colonies we have:
[tex]100e ^ {0.70t} = 300[/tex]
From here, we clear the value of t.
We have then:
[tex]e ^ {0.70t} = \frac {300} {100}\\e ^ {0.70t} = 3\\0.70t = ln (3)\\t = \frac {ln (3)} {0.70}\\t = 1.6 hours[/tex]
Answer:
after 1.6 hours 300 colonies will be present
