Answer:
[tex]a = 9\\b = 48\\c = -1[/tex]
Step-by-step explanation:
We know that:
In a deck of 52 cards there are 4 aces.
Therefore the probability of obtaining an ace is:
P (x) = 4/52
The probability of not getting an ace is:
P ('x) = 1-4 / 52
P ('x) = 48/52
In this problem the number of aces obtained when extracting cards from the deck is a discrete random variable.
For a discrete random variable V, the expected value is defined as:
[tex]E(V) = VP(V)[/tex]
Where V is the value that the random variable can take and P (V) is the probability that it takes that value.
We have the following equation for the expected value:
[tex]E(V) = \frac{4}{52}(a) + \frac{b}{52}(c)[/tex]
In this problem the variable V can take the value V = 9 if an ace of the deck is obtained, with probability of 4/52, and can take the value V = -1 if an ace of the deck is not obtained, with a probability of 48 / 52
Therefore, expected value for V, the number of points obtained in the game is:
[tex]E(V) = \frac{4}{52}(9) + \frac{48}{52}(-1)[/tex]
So:
[tex]a = 9\\b = 48\\c = -1[/tex]
Answer: for question 2, 3 and 4 on that page the answers are 2. -3/13 points: no you should not play the game . 3. E(X)=0 4. 12
Step-by-step explanation:
