In a series circuit, the value of the equivalent resistance [tex]R_E[/tex] is equal to the sum of the values of each of them:
[tex]R_ {E}=R_{1}+R_ {2}+R_ {3}[/tex]
Where:
In this case the current [tex]I[/tex] flowing through the resistors is the same in each one. This is because the current flowing through the circuit only has one way to go, so the current intensity is the same throughout the circuit.
Therefore:
The battery provides a voltage [tex]V_T[/tex] that is the sum of the different voltages at the ends of the resistors:
[tex]V_{T}=V_{1}+V_{2}+V_{3}[/tex]
Where the Voltage, according to Ohm's law is:
[tex]V=R.I[/tex]
Hence, the second statement of this question is True