contestada

A rectangular coil that has a length of 18.0 cm and a width of 6.5 cm containing 11 loops lies flat on your desk as shown on this page. A uniform magnetic field of magnitude 5.20 × 10 − 5 T points towards the right of this page. If a 6.50-A counterclockwise current flows through the coil, (a) determine the torque on the coil.\

Respuesta :

skyluke89

Answer:

[tex]4.35\cdot 10^{-5} Nm[/tex]

Explanation:

The torque exerted on a current-carrying coil by a magnetic field perpendicular to the area of the coil is given by:

[tex]\tau = NIAB[/tex]

where:

N = 11 is the number of loops

[tex]A=18.0 cm \cdot 6.5 cm=117 cm^2 =1.17\cdot 10^{-2} m^2[/tex] is the area of the coil

I = 6.50 A is the current

[tex]B=5.2\cdot 10^{-5}T[/tex] is the magnitude of the magnetic field

Substituting into the equation, we find the torque:

[tex]\tau=(11)(6.50 A)(1.17\cdot 10^{-2} m^2)(5.2\cdot 10^{-5} T)=4.35\cdot 10^{-5} Nm[/tex]

okpalawalter8

The torque on the coil is mathematically given as

T=4.35* 10^{-5} Nm

Torque on the coil

Question Parameters:

a length of 18.0 cm and a width of 6.5 cm containing 11 loops lies flat on your desk as shown on this page. A uniform magnetic field of magnitude 5.20 × 10 − 5 T

Generally the equation for the Torque   is mathematically given as

T=NIAB

Where

A=18.0 cm* 6.5 cm

A=117 cm^2

A=1.17e-2

Therefore

T=NIAB

T=(11*6.50 *1.17* 10^{-2} m^2)(5.2* 10^{-5} T)

T=4.35* 10^{-5} Nm

For more information on Torque

https://brainly.com/question/20691242

Otras preguntas