QUESTION 1
The given function is
[tex]g(x) = 2x + 12[/tex]
This implies that,
[tex]g(x) - 5 = 2x + 12 - 5[/tex]
[tex]g(x) - 5 = 2x + 7[/tex]
We now put x=7 to obtain,
[tex]g(7) - 5 = 2(7) + 7[/tex]
Simplify,
[tex]g(7) - 5 = 14+ 7[/tex]
[tex]g(7) - 5 = 21[/tex]
QUESTION 2
The given pair of points are C(–7, 5) and D(–9, 9).
The is given by the formula:
[tex]m = \frac{y_2-y_1}{x_2-x_1} [/tex]
We plug in the coordinates to obtain,
[tex]m = \frac{9 - 5}{ - 9 - - 7} [/tex]
[tex]m = \frac{4}{ - 2} [/tex]
[tex]m = - 2[/tex]
The slope is
[tex] - 2[/tex]
QUESTION 3
The given function is
[tex]f(x) = - \frac{1}{3}x [/tex]
To evaluate this function for f(4) means we should substitute x=4 into the formula and simplify.
[tex]f(4) = - \frac{1}{3} \times 4[/tex]
[tex]f(4) = - \frac{4}{3} [/tex]
[tex]f(4) = - 1 \frac{1}{3} [/tex]
