Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.
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let f be the female costumes and m be the male costumes:
3f + 4m = 48
3f + 2m = 36
solve simultaneous equations
2m = 12
male = 6 metres
sub vale back in
3f + 2m = 36
3f + (2×6) = 36
3f + 12 = 36
3f = 24
f = 8 metres
each female costume requires 8 metres of fabric and every male costume requires 6 metres of fabric.
We will get the system of equations:
And the solutions are:
x = 8m and y = 12m.
First, we need to define the variables:
We know that for 3 females and 4 males, she sued 48 meters of fabric, then:
3*x + 4*y = 48m
We also know that for 3 females and 2 males, she used 36 meters.
3*x + 2*y = 36m
To solve this, we can take the difference between the two equations to get:
(3*x + 4*y) - (3*x + 2*y) = 48m - 36m
2y = 12m
y = (12m)/2 = 6m
Now that we know the value of y, we can get the value of x by using one of the two given equations:
3x + 2*6m = 36m
3*x + 12m = 36m
3x = 36m - 12m = 24m
x = 24m/3 = 8m
Then, for each female she needs 8m of fabric, and for each male she needs 12m of fabric.
If you want to learn more about systems of equations, you can read:
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