The frozen The yogurt cone shown is made from a cone and a hemisphere. radius is 6 cm. Th e total height of the figure is 24 cm. Suppose the cone is completely packed with frozen yogurt.

The height of the cone is_____cm

The height of the hemisphere is_____cm

The exact volume of the cone is ____ pi cm^3

The exact volume of the hemisphere is ____pi cm ^3

Respuesta :

Answer:

The height of the cone is 18 cm

The height of the hemisphere is 6 cm

The exact volume of the cone is 216 pi cm^3

The exact volume of the hemisphere is 144 pi cm ^3

Step-by-step explanation:

Since the height of the entire figure is 24 then the height of the cone is 18 cm. This is true since a hemisphere is half a sphere and its height will be its radius which is 6. The height if the hemisphere is 6. So 24 - 6 = 18, the height of the cone.

The volume of the cone is found using the volume formula for a cone [tex]V=\frac{1}{3}\pi r^2h[/tex].

Substitute h=18 and r = 6.

[tex]V = \frac{1}{3}\pi r^2h\\V = \frac{1}{3}\pi (6^2)(18)\\V=\frac{1}{3}\pi *36*18\\V = \frac{648}{3}\pi \\V= 216\pi [/tex]

The volume of a hemisphere is half of [tex]V=\frac{4}{3}\pi r^3[/tex]. Substitute r=6.

[tex]V=\frac{4}{3}\pi r^3\\V=\frac{4}{3}\pi 6^3\\V=\frac{4}{3}\pi *216\\V=\frac{4*216}{3}\pi\\ V=288\pi[/tex]

However the hemisphere is half this so it is [tex]144\pi[/tex].