Answer:
y = 2 ± [tex]\sqrt{x^2 - 4x + 4 + C}[/tex]
Step-by-step explanation:
Solve using separable equations
First put x and dx on the same side and do the same for y
(y-2)dy = (x-2)dx
Now you can integrate
[tex]\frac{x^2}{2} +2x + C1 = \frac{y^2}{2} +2y\\[/tex] + C1
Now we depending on how what ur instructor wants you may need to give exact solutions. We can do this by solving he quadratic equation for Y
Doing this you get:
y = 2 ± [tex]\sqrt{x^2 - 4x + 4 + C}[/tex]
Note C's were simplified.
