Respuesta :

Ashraf82

Answer:

The solution is (3 , 1)

Step-by-step explanation:

To solve the system of the equation you can use the elimination method or substitution method.

We will use the substitution method

From the first equation x + 2y = 5⇒get  x = 5 - 2y

In the second equation 3x + 5y = 14⇒we will substitute x by 5 - 2y

3(5 - 2y) + 5y =14

15 - 6y + 5y = 14

-6y + 5y = 14 - 15

-y = -1

y = 1

Substitute the value of y in x = 5 - 2y

x = 5 - 2(1) = 5 -2 =3

∴ The solution of the system of equations is (3 , 1)

zainebamir540

Answer:

Choice 1 is true answer.

Step-by-step explanation:

We have given two equations.

x+2y = 5                        eq(1)

3x+5y = 14                     eq(2).

we use substitution method to solve this system of equations.

From eq(1), separate x.

x = 5-2y                             eq(3)

substituting the value of x in eq(2)

3(5-2y)+5y = 14

15-6y+5y = 14

Adding -15 to both sides of above equation, we have

-15+15-6y+5y =-15+14

Adding like terms ,we have

-y = -1

y = 1

Substituting the value of y in eq(3),we have

x = 5-2(1)

x = 5-2

x = 3

hence, the solution of given system is (3,1).

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