Respuesta :
[tex] \frac{500ml}{} \frac{1l}{1000 \: ml} \frac{1.75x10 ^{ - 2} m}{1 l} \frac{1l}{1m} \: = 8.75ml[/tex]
Of Glucose Stock Solution
Answer : The correct option is, (b) 8.75 ml
Solution :
According to the dilution law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of stock solution = 1.00 M
[tex]V_1[/tex] = volume of stock solution = ?
[tex]M_2[/tex] = molarity of glucose solution = [tex]1.75\times 10^{-2}M[/tex]
[tex]V_2[/tex] = volume of glucose solution = 500 ml
Now put all the given values in the above law, we get the volume of stock solution.
[tex](1.00M)\times V_1=(1.75\times 10^{-2}M)\times (500ml)[/tex]
[tex]V_1=8.75ml[/tex]
Therefore, the volume of 1.00 M stock solution required volume is, 8.75 ml