contestada

Three kids pull on a toy. kim pulls with a force of 30 n north, jim pulls with a force of 30 n south, and tim pulls with a force of 15 n east. the acceleration of the toy is

Respuesta :

As we can see the figure we will have

[tex]F_1 = 30 N[/tex] North

[tex]F_2 = 30 N[/tex] South

[tex]F_3 = 15 N[/tex] East

now for net force on Toy we need to add all forces along with the direction (Vector Sum)

[tex]F = F_1 + F_2 + F_3[/tex]

[tex]F = 30\hat j + 15 \hat i + 30 (-\hat j)[/tex]

now from above we have

[tex]F = 15 N[/tex] towards East

so net force on the toy is 15 N towards East

now the acceleration of toy is given as

[tex]a = \frac{F}{m}[/tex]

[tex]a = \frac{15}{m}[/tex]

here m = mass of toy

Ver imagen aristocles

Otras preguntas