The empirical formula of a chemical compound is the simplest whole number ratio of atoms present in the substance.
The empirical formula of this question is [tex]NH_13C_3O_3[/tex]
Now calculating the empirical formula of the given compound:
The given percentage of the elements:
Nitrogen - 46.67%
Hydrogen - 6.70%
Carbon - 19.98%
oxygen - 26.65%
We need to determine the number of moles of each element using each element's molar mass, which is the :
Molar mass of one mol of nitrogen:
[tex]46.67 \times \frac{1 mol N}{14.007} = 0.478 \;mol N[/tex]
Molar mass of one mol of hydrogen:
[tex]6.70\times \frac{1 mol H}{1.008} = 6.646\;mol\;H[/tex]
Molar mass of one mol of carbon:
[tex]19.98 \times \frac{1molC}{12.010} = 1.663 \;mol\;C[/tex]
Molar mass of one mol of oxygen:
[tex]26.65 \times \frac{1 mol O}{15.999} = 1.665\; mol\; O[/tex]
Determine the mole ratios by dividing the number of moles of each element by the least number of moles :
Nitrogen = [tex]\frac{0.478 mol N}{0.478 mol} = 1\;mol\;N[/tex]
Hydrogen = [tex]\frac{6.646molH}{0.478mol} =\; 13.90mol\;H[/tex]
Carbon = [tex]\frac{1.663molC}{0.478mol} = 3.479\;mol\;C[/tex]
Oxygen = [tex]\frac{1.665molO}{0.478mol} = 3.483\;mol\;O[/tex]
Thus, the empirical formula is [tex]NH_13C_3O_3[/tex].
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