Answer: The potential difference from the sphere's surface to its center is zero.
Explanation:
The expression for the potential difference due to charge is as follows;
[tex]\Delta V=\frac{q}{4\pi \epsilon _{0}r}[/tex]
Here, [tex]\Delta V[/tex] is the potential difference, q is the charge, r is the position and [tex]\epsilon _{0}}[/tex] is the absolute permittivity of free space.
In the given problem, a solid sphere of radius r carries charge q distributed uniformly throughout its volume.
To find the potential difference from the sphere's surface to its center. Put r=0 in the expression of the potential difference.
[tex]\Delta V=\frac{q}{4\pi \epsilon _{0}(0)}[/tex]
[tex]\Delta V=0[/tex]
Therefore, the potential difference from the sphere's surface to its center is zero.
