Answer:
25.44g
Explanation:
Given parameters:
Mass of sodium = 10g
Mass of NaCl produced = ?
Solution
We first write the balanced reaction equation as shown below:
2Na + Cl₂ → 2NaCl
From the information given about the reaction, we know that the chlorine gas is in excess. Sodium reactant is the limiting reagent. The amount of Na will determine the extent of the reaction and the amount of products that would be formed.
Now, we find the number of moles of Na that reacted and we can use the stoichiometeric relationship to determine the number of moles of the NaCl produced. This will then give us our unknown mass of NaCl
Number of moles of Na = [tex]\frac{Mass}{Molar mass}[/tex]
= [tex]\frac{10}{23}[/tex]
= 0.435moles
From the equation of the reaction:
2 moles of Na produced 2 moles of NaCl
0.435 moles of Na will produce 0.435moles of NaCl
To find the mass of NaCl, we use the expression below:
mass of NaCl = number of moles of NaCl x molar mass
Molar mass of NaCl = 23 + 35.5= 58.5g/mol
mass of NaCl = 0.435 x 58.5 = 25.44g
