There are 10 students in a class. The teacher chooses 2 students to go to the library. The order in which they are chosen does not matter. How many ways are there to choose the students?

A permutation is defined as a mathematical process which determines the number of different arrangements in a set of objects when the order of the sequential arrangements.

Given that,

The number of students in a class (p) = 10

The number of students chosen by teacher to go to library (q) = 2

Let The number of ways in which students were chosen = (x) ways

Now, according to question

So, number of ways in which students were chosen = [tex]^pC_q[/tex]

x ways = [tex]\dfrac{10!}{(10-2)!2!}[/tex]

[tex]x =\dfrac{10\times 9\times 8!}{8!\times2!}[/tex]

[tex]x =\dfrac{10\times 9}{2}[/tex]

[tex]x =\dfrac{90}{2}[/tex]

x = 45

Hence, the number of ways in which students were chosen is 45 ways.

Learn more about permutation here:

https://brainly.com/question/1216161

#SPJ5