Answer : Radius of Earth is 6,340 Km.
Explanation
It is given that,
Tangential velocity of Earth at the equator, v = 465 m/s
Centripetal acceleration at the equation is, [tex]a_c=3.41\times 10^{-2}\ m/s^2[/tex]
We know that the relation between centripetal acceleration and tangential velocity is :
[tex]a_c=\dfrac{v^2}{r}[/tex]..........(1)
Where,
v is tangential velocity
r is the radius
Putting all values in equation (1)
[tex]3.41\times 10^{-2}\ m/s^2=\dfrac{(465 m/s)^2}{r}[/tex]
[tex]r=6340909\ m[/tex]
or
[tex]r=6,340\ Km[/tex]
The Earth's radius is 6,340 Km. Hence, this is the required solution.
