A projectile is fired from the origin (at y = 0 m) as shown in the diagram. The initial velocity components are and The projectile reaches maximum height at point P, then it falls and strikes the ground at point Q, which is 20 m below the launch point. What is the vertical component of the velocity (Vy) of the projectile at point P?

Respuesta :

5naka

by the law of exchange of energy

Vy = 0 at point P

Answer:

at highest point [tex]v_y = 0[/tex]

Explanation:

If an object is projected upwards with certain velocity an an angle with horizontal then we will have

[tex]v_x = v_o cos\theta[/tex]

[tex]v_y = v_o sin\theta[/tex]

now we know that the acceleration due to gravity on the object will be in opposite to the vertical velocity

so due to this acceleration due to gravity we can say that its vertical velocity will decrease with time

so as it will move up the vertical velocity will decrease and at the highest point of the motion the vertical velocity will become zero

so at highest point [tex]v_y = 0[/tex]