Answer:
The other dimension of the pasture (width) is [tex]1.625\ mi[/tex]
Step-by-step explanation:
In this problem I assume that the pasture has the shape of a rectangle.
Let
x -----> the length of the pasture
y -----> the width of the pasture
we know that
The area of the pasture (rectangle) is equal to
[tex]A=xy[/tex]
we have
[tex]A=0.65\ mi^{2}[/tex]
[tex]x=0.4\ mi[/tex]
substitute and solve for y
[tex]0.65=0.4y[/tex]
[tex]y=0.65/0.4[/tex]
[tex]y=1.625\ mi[/tex]
