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A bird flies from its nest and lands in a tree that is 2400m due west. If the bird can fly at an average velocity of 9.0m/s, for how long, in seconds, is the bird in flight?

Respuesta :

Answer: 266.67 s

Explanation:

Average velocity is the rate of change of displacement.

Bird flies 2400 m due west at an average velocity of 9.0 m/s.

[tex]\text{Average velocity}=\frac{Displacement}{time}[/tex]

Given, average velocity, v = 9.0 m/s

Displacement, d = 2400 m

[tex]v=\frac{d}{t}\Rightarrow t=\frac{d}{v}\\ t=\frac{2400 m}{9.0,m/s}=266.67s[/tex]

Thus, bird was in flight for 266.67 s to fly from nest to land in a tree 2400 m due west.

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