Respuesta :
Answer:
[tex]\large\boxed{x<-8}[/tex]
Step-by-step explanation:
[tex]3-(2x-5)<-4(x+2)\qquad\text{use distributive property}\\\\3-2x-(-5)<-4x+(-4)(2)\\\\3-2x+5<-4x-8\\\\-2x+(5+3)<-4x-8\\\\-2x+8<-4x-8\qquad\text{subtract 8 from both sides}\\\\-2x<-4x-16\qquad\text{add 4x to both sides}\\\\2x<-16\qquad\text{divide both sides by 2}\\\\x<-8[/tex]