using the first kinematics equation
the initial velocity will be
V = U + at
v is final velocity and u is the initial velocity and a is an acceleration and t is the time period
2.75 = u - 0.5*2
2.75 = u-1
3.75 = u thus it will be 3.75 m/s
A bee moving at 3.75 m/s has a final speed of 2.75 m/s after experiencing an acceleration leftward of 0.50 m/s² for 2.0 s.
A bumblebee is flying to the right when a breeze causes the bee to slow down with a constant acceleration of 0.50 m/s² leftward. After 2.0s, the bee's speed is 2.75 m/s to the right. How fast was the bumblebee flying before the breeze?
A bee is moving to the right with an unknown initial speed (u). After suffering an acceleration (a) of -0.50 m/s² (the negative sign indicates that it is leftward) for 2.0 s (t), it has a final speed (v) of 2.75 m/s.
We can calculate the initial speed of the bee using the following kinematic equation.
[tex]a = \frac{v-u}{t} \\\\u = v-a \times t = 2.75 m/s - (-0.50 m/s^{2} ) \times 2.0 s = 3.75 m/s[/tex]
A bee moving at 3.75 m/s has a final speed of 2.75 m/s after experiencing an acceleration leftward of 0.50 m/s² for 2.0 s.
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