Answer:
[tex]x^2+4x-12=0[/tex]
Step-by-step explanation:
If a equation has two zeros x=a and x=b then equation can be written as
[tex](x-a)(x-b)=0[/tex]
similarly if a equation has two zeros at x = −6 and x = 2
then equation can be written as
[tex](x+6)(x-2)=0[/tex]
[tex]x^2+6x-2x-12=0[/tex]
[tex]x^2+4x-12=0[/tex]
Therefore [tex]x^2+4x-10[/tex] is required equation
Answer:
x²+4x - 12 = 0 is the answer.
Step-by-step explanation:
We have to drive the equation that is true for x = -6 and x = 2.
If the equation has two zeros then equation is of the form as below:
(x-c)(x-d) = 0
We simplify the equation when the equation has zeros at x = -6 and x= 2.
(x-(-6))(x-2)=0
(x+6)(x-2) = 0
x²-2x+6x-12 = 0
x²+4x - 12 = 0
x²+4x - 12 = 0 is the answer of given expression.
