Answer:
f(x)=[tex]x^2-3x-10[/tex]
Step-by-step explanation:
If a function has two zeros x=a and x=b then function can be written as
[tex](x-a)(x-b)[/tex]
similarly if a function has two zeros at x = −2 and x = 5
then function can be written as
[tex](x+2)(x-5)[/tex]
[tex]x^2-5x+2x-10[/tex]
[tex]x^2-3x-10[/tex]
Therefore f(x)=[tex]x^2-3x-10[/tex] is required function
Answer:
f(x) = x²-3x-10 is the answer.
Step-by-step explanation:
We have to find the function that has zeros at x = -2 and x=5 .
Function that has two zeros is of the form :
(x-c)(x-d) = 0
If the function has two zeros at x = -2 and x=5 then it is of the form:
(x-(-2))(x-5)=0
(x+2)(x-5) = 0
(x+2)(x-5) = 0
x²-5x+2x-10 =0
x²-3x-10 = 0 is the function has zeros at x = −2 and x = 5.
