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What is the slope of the line that contains the points (-23, -16) and (13, -16)?What is the slope of the line that contains the points (-2, 1) and (0, -3)?

Respuesta :

sqdancefan

Answer:

  1. the slope is 0 (zero)
  2. the slope is -2

Step-by-step explanation:

1.  Slope is the ratio of (change in y) to (change in x). Here there is no change in y. (y is constant at -16) So, the slope is zero (0).

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2. The change in y is (-3 -1) = -4. The change in x is (0 -(-2)) = 2. The ratio of change in y to change in x is ...

  slope = (change in y)/(change in x) = -4/2 = -2

CharlieBrown2002

Answer:

1. Slope is 0

2. Slope is -2

Step-by-step explanation:

1. (-23,-16) and (13,-16)

Slope formula

[tex]\displaystyle \frac{y_2-y_1}{x_2-x_1}=\frac{rise}{run}[/tex]

[tex]\displaystyle \frac{(-16)-(-16)}{13-(-23)}=\frac{0}{36}=0[/tex]

The slope is 0.

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2. (-2,1) and (0,-3)

[tex]\displaystyle \frac{(-3)-1}{0-(-2)}=\frac{-4}{2}=-2[/tex]

The slope is -2.

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