Plz help! Number 6 please!
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Answer:
The last 2 statements are true
Step-by-step explanation:
given f(x) = x² + 6x and g(x) = 2x³
f(x) × g(x) = 2x³(x² + 6x) = 2[tex]x^{5}[/tex] + 12[tex]x^{4}[/tex]
not 2[tex]x^{5}[/tex] + 12x³
f(0) = 0 + 0 = 0 and g(2) = 2 × 2³ = 2 × 8 = 16
f(0 × g(0) = 0 × 16 = 0 ≠ 16
f(1) = 1 + 6 = 7 and g(1) = 2 × 1³ = 2
f(1) × g(1) = 7 × 2 = 14 ← True
g(x) × g(x) = 2x³ × 2x³ = 4[tex]x^{(3+3)}[/tex] = 4[tex]x^{6}[/tex] ← True
Answer: (C) f(1)·g(1) = 14 and (D) g(x)·g(x) = 4x⁶
Step-by-step explanation:
f(x) = x² + 6x g(x) = 2x³
f(x) · g(x) = (x² + 6x)( 2x³)
= 2x⁵ + 12x⁴ not equal to 2x⁵ + 12x³ (FALSE)
f(0) = 0² + 6(0) g(2) = 2(2)³
= 0 + 0 = 2(8)
= 0 = 16
f(0) · g(2) = 0 · 16
= 0 not equal to 16 (FALSE)
f(1) = 1² + 6(1) g(1) = 2(1)³
= 1 + 6 = 2(1)
= 7 = 2
f(1) · g(1) = 7 · 2
= 14 equal to 14 (TRUE)
g(x) · g(x) = (2x³)(2x³)
= 4x⁶ equal to 4x⁶ (TRUE)