Hello from MrBillDoesMath!
Answer:
20
Discussion:
Let (x1,y1) = (-8, -6) and (x2,y2) = (4,10). Per the distance formula,
Distance = sqrt ( (x1-x2)^2 + (y1-y2)^2 ) so
Distance = sqrt ( (-8-4)^2 + (-6-10)^2 )
= sqrt( (12)^2 + (-16)^2 )
= sqrt( 144 + 256 )
= sqrt(400)
= 20
Thank you,
MrB
Answer: 20
Step-by-step explanation: Draw lines connecting (-8,-6),(4,10) and a hypotenuse line across so you should have a triangle. (I am assuming you have done this before) Then you use the Pythagorean Theorem to calculate the hypotenuse of the triangle you just drew.
[tex]a^{2} +b^{2} =c^{2} \\12^{2} 16^{2} =400\\\sqrt{400} =20[/tex]
