A plane flew 720 mi with a steady 30 mi/h tailwind. The pilot then returned to the starting point, flying against that same wind. If the round trip flight took 10 h, what was the plane's airspeed?

PLEASE HELP ASAP!!

Respuesta :

Answer:

Plane's speed is 150 miles/hour

Step-by-step explanation:

Let the plane's airspeed be x

Speed of wind is 30 miles/hour

When a plane flew with the wind , Speed = (x+30)

So, the speed plain with wind on going = (x+30)

Since we are given that on returning plane fly against the wind .

So,When a plane flew against the wind , Speed = (x-30)

So, the speed plain against wind on returning = (x-30)

Distance = 720 miles .

[tex]Time = \frac{Distance}{Speed}[/tex]

So, time on going  [tex]=\frac{720}{(x+30)}[/tex]

Time on returning  [tex]=\frac{720}{(x-30)}[/tex]

Now we are given that the total time for the whole trip (going + returning) = 10 hours.

So,  [tex]\frac{720}{(x+30)}+\frac{720}{(x-30)}=10[/tex]

[tex]\frac{720x-21600+720x+21600}{(x+30)(x-30)}=10[/tex]

[tex]720x-21600+720x+21600=10(x+30)(x-30)[/tex]

[tex]720x+720x=10(x+30)(x-30)[/tex]

[tex]1440x=10(x^2 -[30]^2)[/tex]

[tex]144x=x^2 -900[/tex]

[tex]x^2-144x -900=0[/tex]

[tex]x^2-150x+6x -900=0[/tex]

[tex]x(x-150)+6(x -150)=0[/tex]

[tex](x-150)(x+6)=0[/tex]

[tex]x= 150,x= -6[/tex]

So, the plane's speed is 150 miles/hour