Answer:
PS=[tex]\sqrt{26}units[/tex]
Step-by-step explanation:
Given : PQRS is a trapezoid on a coordinate plane P(7,4) Q(10,4) R(13,-1) S(8,-1).
To find:: Length of the side PS
Solution : Using the distance formula, we can find the length of the side PS, therefore
PS=[tex]\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2}[/tex]
PS=[tex]\sqrt{(-1-4)^{2}+(8-7)^2 }[/tex]
PS=[tex]\sqrt{(-5)^2+(1)^2}[/tex]
PS=[tex]\sqrt{25+1}[/tex]
PS=[tex]\sqrt{26}units[/tex]
which is the required length of the side PS.
